Question

Hydrogen atom is excited by 10.2 ev the maximum number of spectral lines in the emmission

Answer 1

E µ 1/n2

For n=1, E = 13.6 eV

Thus energy absorbed =13.6 (1 - (1 / n2) eV., where n =1 to ¥

For n=2, E = 13.6(1 - (1 / 22) = 10.2

This is the lowest energy state possible for emission of spectral lines.

Thus the energy absorbed should always be between 10.2 and 13.6 eV

Hence , no emission takes place when hydrogen atom is excited by giving 8.4eV.