hydrogen atom the electron revolves around the proton in a circular orbit of radius 0.528 a with a speed of 2.18 multiply 10 power 6 metre per second calculate the centripetal force acting on the electron.....
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hydrogen atom the electron revolves around the proton
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Centripetal velocity (v)
Centripetal velocity (v)Radius (r)
Centripetal velocity (v)Radius (r)Centripetal Acceleration (a)
Centripetal velocity (v)Radius (r)Centripetal Acceleration (a)Now we use the formula, a= v^2/r
Therefore, a = (2.18 × 10^6)^2/ 5.28 × 10^-11
a = 4.7524 × 10^12 / 5.28 × 10^-11
a = 9.0007 × 10^22
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