Question

solve the following quadratic equation by method of perfect square :
2x²+x-4=0

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Answer 1

Step-by-step explanation:

$2 {x}^{2} + x - 4 = 0 = > 2( {x}^{2} + \frac{x}{2}) - 4 =$

$0 = > {x}^{2} + 2.x. \frac{1}{4} + { \frac{1}{4} }^{2} - { \frac{1}{4} }^{2} - 4 = 0$

$= > {(x + \frac{1}{4})}^{2} - \frac{65}{16} = 0 = >$

$((x + \frac{1}{4}) + \frac{ \sqrt{65} }{4} )((x + \frac{1}{4}) - \frac{ \sqrt{65} }{4}) = 0$

So x = -(√65+1)/4 and x = (√65-1)/4 are roots of the above equation. Hope it helps you.

Answer 2

Answer:

Step-by-step explanation:

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