Question

Hydrogen like atom when an electron jumps from M shell to l wavelength emitted radiation is Lambda if an electron jumps from pencil to LCL wavelength of emitted tradition will be

Answer 1

Answer:For M

→

L steel

1

λ

=

K

(

1

2

2

−

1

3

2

)

=

K

×

5

36

for N

→

L

1

λ

′

=

K

(

1

2

2

−

1

4

2

)

=

K

×

3

16

λ

′

=

20

27

λ

.

Answer 2

If an electron jumps from N-shell to the L-shell, the wavelength of emitted radiation will be 20λ/27

Given-

• When electron jumps from N-shell to L- shell the wavelength of emitted radiation = λ

For M to L transition, n₁ = 2 and n₂ = 3

1/λ = K (1/2² - 1/3²) = 5 K/36

For N to L transition, n₁ = 2 and n₂ = 4

1/λ' = K (1/2² -1/4²) = 3 K/16

From the above two equations-

λ' = 20λ/27