Question

hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the equation,2H2O2(aq)--->H2O(l)+O2(g)( under conditions where one mole of gas occupies 24dm^3).100cm^3 of X M solution of H2O2 produces 3dm^3of O2. thus X is​

Answer 1

Answer:

X is 2.5

Explanation:

The given chemical equation for the decomposition of Hydrogen Peroxide (H₂O₂) is

2H₂O₂ (aq) → 2H₂O (l) + O₂ (g)

From the above equation 2 moles of H₂O₂ produces 1 mole of O₂

Given that 100 ml (1 cc = 1 ml) of X M solution of H₂O₂ produces 3 dm³ of O₂

Also 1 mole of O₂ occupies 24 dm³ of space

Thus, 1/8 moles of  O₂ will occupy 3 dm³ of space

Therefore the moles of H₂O₂ = 2 × 1/8 = 1/4 = 0.25

In 100 mL moles of H₂O₂ = 0.25

In 1000 mL moles of H₂O₂ = 2.5

Therefore, the molarity of H₂O₂ = 2.5 M

Thus, X = 2.5 M

Hope this helps.

Answer 2

Answer:

3L of O2 is produced, no. of moles = 3/24 = 0.125mol

2 mol H2O2 react to produce 1 mol O2, therefore there must be 0.125*2 = 0.250mol of H2O2

Now, molarity = n/V

V = 100mL = 0.1L

Therefore, x = 0.25/0.1 = 2.5 M (option A)

Explanation: