Hydrogen sulphide (H2S) is a strong reducing agent.
Which of the following reactions shows its reducing
action -
(a) Cd(NO3)2 + H2S- CdS+2HNO3
(b) CuSO4 + HS - Cus + H2SO4
(c) 2FeCl3 +H2S - 2FeCl2+2HCI+S
(d) Pb(NO3)2 +H2S - PBS + 2CH3COOH
Answers
Answered by
31
answer : option (c)
explanation : we know , reducing agent oxidizes itself and reduces other.
in option (c) ;
here, oxidation number or O.N of Fe in FeCl3 = +3
O.N of S in H2S = -2
O.N kf Fe in FeCl2 = +2
Oxidation number of S = 0
it is clear that, Fe is reduced from +3 to +2 whereas S is oxidised from -2 to O.
hence, this reaction shows that H2S is strong reducing agent.
hence, option (C) is correct choice.
Answered by
8
Answer:
Explanation:
Option "C"
Hope you must hv got it....
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