Question

Hydrogenation of vegetable ghee at 25 c reduce pressure of h2 from 2 atm to 1.2 atm in 50 minute. The rate of reaction in terms of molarity per second is

Answer 1

Answer:

The rate of reaction in terms of molarity per second is 1.09*10⁻⁵ mil litre⁻¹ sec⁻¹

Explanation:

given :

Temperature=25⁰c=25+ 273=298K

Assuming H2 as an Ideal gas.

Change in molarity= n/V= ΔP/ RT

= 0.8/0.0821x298

≈0.0327

Rate of reaction= change in molarity/sec

= 0.0327/50x60

=1.09x 10⁻⁵ mil litre⁻¹ sec⁻¹

Answer 2

Answer:

Refer the above attachment