Question

Hypoleuse.
4. The perimeter of a triangular field is 240m. Its two sides are 78 m and 50 m. Find the
length of the altitude on the side of 50 m length from its opposite vertex.
5. The area of a quadrilateral is 360 m2 and the perpendiculars drawn to​

Answer 1

Answer:

height=1.12$\sqrt{30}$

Step-by-step explanation:

let the unknown side of triangle be x.

perimeter of triangular field=78+50+x

240=128+x

x=112 m

by appling heron's formula:-

s=perimeter/2=120

area=$\sqrt{(s-a)(s-b)(s-c)}$

=$\sqrt{(120-78)(120-50)(120-112)}$

=$\sqrt{42*70*8}$

=$28\sqrt{30}$

area of triangle=1/2*base*height

$28\sqrt{30}$=1/2*50*height

$28\sqrt{30}$/25=height

height=1.12$\sqrt{30}$