Physics, asked by Anonymous, 8 months ago

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A body starting from rest slides on an inclined plane AB of length l of inclination theta. Calculate the time of descent and speed at the bottom. Find also:
a) distance covered in half the time of descent and
B) time taken to cover half the distance.


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adiii22 avatar

adiii22

12.04.2020

Math

Secondary School

+5 pts

Answered

Starting from rest at the top of an inclined plane a body reaches the

bottom of the inclined plane in 4 second. In what time does the body

cover one-fourth the distance starting from rest at the top?

1

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IamTejas

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Answer: 2 seconds

Step-by-step explanation:

Let the length of the inclined plane be= L

Let the acceleration of the body while sliding be= a

The initial velocity (u) = 0

The time of sliding L distance is 4s,

So,

L = 0 × 4 + 1 2 × a × 4 2

L = 8 a (Mark this as equation 1)

Let the time of sliding of L/4 length from the top when starting from rest be t s,

So,

L 4 = 0 × t + 1 2 a t 2

L 4 = 1/2at 2 (Mark this as equation 2)

Comparing [1] and[2]

8 a 4 = 1 2 a t 2

=t 2 = 4

t = 2

Therefore, Time= 2s

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