Question

hyyyy mates....

what is law of conservation of linear momentum.....
full defination and drived formula plzzzz...

tommarow is my phy. exam.....plzzz help..

Cherryblossum....​

Answer 1

Answer:

The law of conservation of linear momentum states that if no external forces act on the system of two colliding objects, then the vector sum of the linear momentum of each body remains constant and is not affected by their mutual interaction.

Refer attachments for derivation

Answer 2

Answer:

hi friend

here is ur answer

Conservation of Linear Momentum Formula

The principle of conservation of momentum states that if two objects collide, then the total momentum before and after the collision will be the same if there is no external force acting on the colliding objects.

Derivation:

Let,

mA = Mass of ball A

mB= Mass of ball Ba

uA= initial velocity of ball A

uB= initial velocity of ball B

vA= Velocity after collision of ball A

vB= Velocity after collision of ball B

Fab= Force exerted by A on B

Fba= Force exerted by B on A

Now,

Change in momentum of A= momentum of A after collision - momentum of A before collision

= mA vA - mA uA

Rate of change of momentum A= Change in momentum of A/ time taken

= mA vA - mA uA/t

Force exerted by B on A (Fba)=

Fba= mA vA - mA uA/t. [i]

In the same way,

Rate of change of momentum of B=

mV vB - mB uB/t

Force exerted by A on B (Fab)=

Fab= mB vB - mB uB/t. [ii]

Newton's third law of motion states that every action has an equal and opposite reaction, then,

Fab= -Fba [ ' -- ' sign is used to indicate that 1 object is moving in opposite direction after collision]

Using [i] and [ii] , we have

mB vB - mB uB/t = - (mA vA - mA uA/t)

mB vB - mB uB= - mA vA + mA uA

Finally we get,

mB vB + mA vA = mB uB + mA uA

This is the derivation of conservation of linear momentum.

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