Question

(i) 12, 15, 20, 27 (ii) 22, 54, 108, 135, 198.
36. Find the smallest number which leaves remainders 8 and 12 when divided by 28 and 2
respectively.
37. Find the largest number of three digits which is exactly divisible by 96 and 240​

Answer 1

Answer:

36) 204

37) 480.

Step-by-step explanation:

36) Divisors are 28 & 32, as required. Remainder are also the required number 8 & 12. Hence 204 is the required answer.

37) Answer. LCM of 96 and 240 = 2*2*2*2*2*3*5 = 480.