[i^19 +(1/25)^25]^2 simplify this
(a) -4
(b) 4-1
(c) 2+i
(d) None Of the above
karthik4297:
i think ans will be -1
will u please explain this
sorry ,i calculated it with the help of calculator
i can do it later
it's fine
ok
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[i^19 + (1/25)^25]^2
i^19 = -i
(1/25)^25 = 25^(-25)
Thus [i^19 + (1/25)^25]^2 = [ 25^(-25) - i]²
= (25^(-25))² - 2×(25^(-25)(i)+ (-i)²
=25^(-50) - (2×(25^(-25)) i - 1
=[ -1 + 25^(-50) ] - (2×(25^(-25)) i (exact answer)
-1 + 25^(-50) ≈ -1
2×(25^(-25) ≈ 2.25×10^(-35) ≈ 0
thus -1 is the approximated answer
i^19 = -i
(1/25)^25 = 25^(-25)
Thus [i^19 + (1/25)^25]^2 = [ 25^(-25) - i]²
= (25^(-25))² - 2×(25^(-25)(i)+ (-i)²
=25^(-50) - (2×(25^(-25)) i - 1
=[ -1 + 25^(-50) ] - (2×(25^(-25)) i (exact answer)
-1 + 25^(-50) ≈ -1
2×(25^(-25) ≈ 2.25×10^(-35) ≈ 0
thus -1 is the approximated answer
Ssss118, happy now?
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