(i) 2(2x
2 + xy − z
2
) − xy , when x = 2, y = (-1) and z = (-2)
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0
Answer:
Solution
(xy+yz)
2
−2x
2
y
2
z when x=−1,y=1,z=2
⇒[y(x+z)]
2
−2x
2
y
2
z
⇒y
2
[x
2
+z
2
+2xz−2x
2
z]
⇒(1)
2
[(−1)
2
+2
2
+2(−1)(2)−2(−1)
2
(2)]
⇒[1+4−4−4]⇒−3
∴(xy+yz)
2
−2x
2
y
2
z at x=−1,y=1 and z=2 is −3
Step-by-step explanation:
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Answered by
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Answer:
2 ( 2×
i hope it well help you
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