I(2+i)^2/2-i - (2-i)^2/2+I=?
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Integral powers of i i =1− , i 2 = – 1, i 3 = i 2 i = – i , i 4 = (i 2)2 = (–1)2 = 1. To compute in for n > 4, we divide n by 4 and write it in the ...
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