Question

i^2+i^4+i^6...upto(2n+1) terms is?
CHAPTER IS COMPLEX NUMBERS
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Answer 1

Answer:

-1

Step-by-step explanation:

the given sum is

(i^2)^1 + (i^2)^2 + (i^2)^3 + ......(i^2)^(2n+1)

(-1)^1+(-1)^2+(-1)^3+.....(-1)^(2n+1)

-1+1-1+1-1+.......for 2n+1 terms

since 2n+1 is odd the sum will be -1