Question

i 2x*x+ (k-3) x + (3x-5)=0
roots
are
equal,find the value of k​

Answer 1

Answer:

3

Step-by-step explanation:

2x*x+(k-3)x+(3x-5)=0,rots are equal

=2x*x+kx-3x+3x-5=0

=2x*x+kx=5[as -3x and +3x cancels]

=x(2x+k)=5

=2x+k=5/x

=k=5/x-2x

=k=3x/x

=k=3[as x and x cancels]

Answer 2

Answer:

3

Step-by-step explanation:

2x*x+(k-3)+(3x-5)=0,roots are equal.

2x*x+kx-3x+3x-5=0

2x*x+Kx = 5(as -3x and + 3x cancels)

x(2x+k)=5

2x+ 5=5/x

k=5/x -2x

k=3x/x

k=3(as x and x cancels)

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