i) 3^x = 5^x-2 solve in logarithms
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Answer
Solve 3
x
=5
x−2
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3
x
=5
x−2
Apply log on both sides
log3
x
=log5
x−2
xlog3=(x−2)log5
xlog3=xlog5−2log5
2log5=xlog(5−3)
2log5=xlog2
log
2
2log5
=x
log
2
log5
2
=x
log
2
log25
=x
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