Question

i=30°, r=30°, angle between the reflected Ray and surface =​

Answer 1

Answer:

To calculate the value of g, we should put the values of G, M and R 

Where G=universal gravitational constant, G=6.7×10–11Nm2kg−2 

mass of the earth, M=6×1024kg, 

and radius of the earth, R=6.4×106m.

g=R2GM

g=(6×106)26.67×10−11×6×1024=9.8m/s2

 Thus, the value of acceleration due to gravity of the earth, g=9.8m/s2

Also we know Weight in nothing but the force exerted by the earth with a value of acceleration =9.8m/s2

Now at the poles the value of acceleration due to gravity is higher as compared to the equator as the constant value of 

g depends on the radius of the earth which decreases when we come down from poles to the equator. 

Explanation:

Q: Derive the equation g.