Question

I 33. Prove that
cose+sine cos' e-sin'e
cos O + sin cos - sin
+
= 2
it's urgent
no irrelevant ans.
​

Answer 1

Answer:

xsin

3

θ+ycos

3

θ=sinθcosθ

(xsinθ)sin

2

θ+(ycosθ)cos

2

θ=sinθcosθ

(xsinθ)sin

2

θ+(xsinθ)cos

2

θ=sinθcosθ

xsinθ=sinθcosθ

x=cosθ

Again, ycosθ=xsinθ

ycosθ=cosθsinθ

y=sinθ

Therefore,

x

2

+y

2

=sin

2

θ+cos

2

θ=1.