Question

(i) (3x – 4y) (4x+y + 3xy?); x = 2, y = -1​

Answer 1

[ 3(2) - 4 (-1) ] × [ 4(2) + (-1) + 3(2)(-1) ]

[6 - (-4) ] × [8-1 + (-6) ]

[6+4] × [7-6]

10 ×1

10

Answer 2

Answer:

$(3x - 4y)(4x + y + 3xy)$

$[3 \times 2 - 4 \times ( - 1)] [ 4 \times 2 + ( - 1) + 3 \times 2 \times - 1]$

$[6 + 4][8 - 1 - 6]$

$10 \times 8 - 7$

$10 \times 1$

$10$