Question

i^47 =
fast please.............​

Answer 1

Answer:

The answer will be i^47 = -i

Step-by-step explanation:

47/4= 11 remainder 3

Using the knowledge of imaginary number series table....

i^47

=(i^4)^11×i^3

=(1)^11×i^3

=1×i^3

=i^3

= (-i)

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