(i) 5(y-3) = 3(2y+1)
iii) 4(22-3)+3 = 2(z+3)-3(z+1)
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- (i) 5(y - 3 ) = 3(2y + 1)
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- (ii) 4(22 - 3) + 3 = 2(z + 3) - 3(z + 1)
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