i 526 find complex number
Answers
Answered by
0
Answer:
Let z=x+iy
then
∣
∣
∣
∣
∣
∣
z+3i
z−3i
∣
∣
∣
∣
∣
∣
≤
2
∣
∣
∣
∣
∣
∣
x+iy+3i
x+iy−3i
∣
∣
∣
∣
∣
∣
≤
2
∣
∣
∣
∣
∣
∣
x+i(y+3)
x+i(y−3)
∣
∣
∣
∣
∣
∣
≤
2
x
2
+(y−3)
2
≤
2
x
2
+(y+3)
2
On squaring on both sides, we get
x
2
+(y−3)
2
≤2(x
2
+(y+3)
2
)
x
2
+y
2
+9−6y≤2x
2
+2y
2
+18+12y
x
2
+y
2
+18y+9≥0
A circle with centre (0,−9) and radius 6
2
units.
Step-by-step explanation:
Let z=x+iy
then
∣
∣
∣
∣
∣
∣
z+3i
z−3i
∣
∣
∣
∣
∣
∣
≤
2
∣
∣
∣
∣
∣
∣
x+iy+3i
x+iy−3i
∣
∣
∣
∣
∣
∣
≤
2
∣
∣
∣
∣
∣
∣
x+i(y+3)
x+i(y−3)
∣
∣
∣
∣
∣
∣
≤
2
x
2
+(y−3)
2
≤
2
x
2
+(y+3)
2
On squaring on both sides, we get
x
2
+(y−3)
2
≤2(x
2
+(y+3)
2
)
x
2
+y
2
+9−6y≤2x
2
+2y
2
+18+12y
x
2
+y
2
+18y+9≥0
A circle with centre (0,−9) and radius 6
2
units.
Similar questions