Question

(i) A gun of mass 4 Kg fires a bullet of 10 g with a speed of
100 m/s in the forward direction. Find
(a) The total initial momentum
(b)The recoil velocity of gun.

Answer 1

Rate of change of momentum of the bullet in the forward direction

= Force required to hold the gun=

t

Δp

P

bullets

=20×10

−3

×300=6

so four bullet fire in 1 sec is 4, therefore P

bullet

=4×6=24

as we have to find the force to hold the gun i.e, P

gun

=0 as it is in steady state

so Net change in momentum i.e, ΔP=0−24=−24 -ve sign means it will recoil in a backward direction.

F=

t

ΔP

=

1

24

=24N

Answer 2

Answer:

(1)A gun of mass 4 kg fires A bullet of 10 gram with a speed of 100 M per second in the forward direction. Find the total initial Momentum and the recoil velocity of gun. The negative sign implies the revolver recoils in the direction opposite to that of the bullet.