Question

i) a1 = 3 and an = 3an + 1 + 2 for all n>1; solve please from AP​

Answer 1

$\sf\small{ \underline{\underline\red{ \pmb{ Answer \: is \: in \: attachment.}}}}$

Answer 2

t1=3. t1 = a = 3

tn= 3an+3.

t2= 9(2)+3 = 21

t3= 9(3)+3 = 30

t4= 9(4)+3 = 39

d= t2-t1 = t3-t2 = 30-21= 39-30 = 9

An = 3an + 1 + 2 for all n>1 is in the form of AP