Question

i)(ACE)16=(?)2

ii)(504)10=(?)2

iii)(11011)2=(?)10

iv)(101101)2+(10011)2=(?)2

v)(1101011)2-(110110)2=(?)2

vi)(414)8=(?)10

vii)(722)10=(?)8

viii)1011011×10=(?)2

ix)(BDE)16=(?)2

x)(548)8=(?)2. . Those who answer all the question correctly he will get brilliant point and no rubish answer good luck ​

Answer 1

Answer:

1

this is the answer and explaination