Question

i am a four digit number with no 4 digits repeated,all four digits are odd excluding the digit 5.The second digit is 7 times the first digit and the last digit is 3 times the third digit.who am i?

Answer 1

Answer:

1739

Step-by-step explanation:

ABCD be the 4 digit number.

*Given*

All digits are odd (and 5 is not there)

So, the remaining odd digits are:

1, 3, 7, 9

The second digit is 7 times first.

So 17 are the first 2 digits

Last digit is 3 times third

Remaining odd digits==3, 9

Third and fourth digits are 39

So ABCD ==1739

I am :

1739