I am a rectangle 2x+y+8, x+4,4x-y,2y
Find the values of x and y
Find my perimeter and area
Answers
Answered by
151
Hey dear,
◆ Answer-
A = 640 sq.units
P = 112 units
◆ Explanation-
# Given-
4 sides of rectangle-
2x+y+8
x+4
4x-y
2y
# Solution-
In a rectangle opposite sides are equal.
2x+y+8 = 4x-y
2x-2y-8 = 0
x-y-4 = 0 ...(1)
x+4 = 2y
x-2y+4 = 0 ...(2)
Solving (1) & (2),
x = 12 units
y = 8 units
Thus
length l = 4x-y = 4×12 - 8 = 40 units
Breadth b = 2y = 2×8 = 16 units
Perimeter
P = 2(l+b)
P = 2(40+16)
P = 112 units
Area
A = l×b
A = 40×16
A = 640 sq.units
Hope that is helpful...
◆ Answer-
A = 640 sq.units
P = 112 units
◆ Explanation-
# Given-
4 sides of rectangle-
2x+y+8
x+4
4x-y
2y
# Solution-
In a rectangle opposite sides are equal.
2x+y+8 = 4x-y
2x-2y-8 = 0
x-y-4 = 0 ...(1)
x+4 = 2y
x-2y+4 = 0 ...(2)
Solving (1) & (2),
x = 12 units
y = 8 units
Thus
length l = 4x-y = 4×12 - 8 = 40 units
Breadth b = 2y = 2×8 = 16 units
Perimeter
P = 2(l+b)
P = 2(40+16)
P = 112 units
Area
A = l×b
A = 40×16
A = 640 sq.units
Hope that is helpful...
Answered by
54
Step-by-step explanation:
perimeter
p=2 (l+b)
p=112,unit
Area
A=l×b
A=640sq unit
Attachments:
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