I am challenging every brainly member to do this question... with steps no direct answer
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Valency of X, Y, Z=1,3,4.
ATOMIC MASS OF Z=ATOMIC MASS OF Y - ATOMIC MASS OF X=102-62=40.
THEREFORE, THE ELECTRONIC CONFIGURATION =2,8,18,8,4.
THE VALENCY IS 4 SINCE THE LAST SHELL WILL HAVE 4 VALENCED ELECTRONS.
THEREFORE, THE ATOMIC NUMBER OBTAINED WOULD BE THE VALENCY OF ELEMENT Z. (ANSWER).
THIS IS THE ONLY ANSWER AND DON'T TRY TO DELETE THIS AGAIN.
Regards,
Shatanik
ATOMIC MASS OF Z=ATOMIC MASS OF Y - ATOMIC MASS OF X=102-62=40.
THEREFORE, THE ELECTRONIC CONFIGURATION =2,8,18,8,4.
THE VALENCY IS 4 SINCE THE LAST SHELL WILL HAVE 4 VALENCED ELECTRONS.
THEREFORE, THE ATOMIC NUMBER OBTAINED WOULD BE THE VALENCY OF ELEMENT Z. (ANSWER).
THIS IS THE ONLY ANSWER AND DON'T TRY TO DELETE THIS AGAIN.
Regards,
Shatanik
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