I am eight times as old as you were when i was as old as you are, said a man to his son. Find out their present ages if the sum of their ages is 75 years. (a) 40 years and 35 years (b) 56 years and 19 years (c) 48 years and 27 years (d) none of thes
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Answered by
68
Answer:
C
Step-by-step explanation:
Let 'x' be the present age of the man,
Let 'y' be the present age of the son,
Given that man was 8 times as old as when the man was as old as son at present
=> before x - y years
Man's Age = y years
Sons Age = y - (x - y)
= 2y - x
Given x = 8(2y-x)
=> 16y = 9x.
Also given Sum of their present ages is 75 years
=> x + y = 75
=> 9x + 9y = 75*9 = 675
=> 16y + 9y = 675
=> y = 27 and x = 48.
Hope, it helped !
Answered by
16
Step-by-step explanation:
Let Boys present age x .....past age y
then father present age will be 8x and pasr age will be x
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