"I am five times as old as you were, when I was as old as you are", said a man to his son. Find out their present ages, if the sum of their ages is 64 years ?
The answer was son=24 and man=40 years, but if man = 24 years then son = 8 years which is not 5 times as in question....
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The question meant that he is five times his son's age when he was of his age.
Father's present age=x Son's present age=y
Now father tells that he was of y age and his son was of age y-(x-y).
So x+y=64
x=5[y-(x-y)]
x=5[y-x+y]
x=5[2y-x]
x=10y-5x
x+5x=10y
6x=10y
x=10y/6
10y/6+y=64
10y/6+6y/6=64
16y=64*6
16y=384
y=384/16
y=24=Son's age
x+24=64
x=64-24
x=40=Father's age
y-(x-y)=24-(40-24)
=24-16
=8
Your doubt=8(son's previous age)
40=5(8)
40=40
Father's present age=x Son's present age=y
Now father tells that he was of y age and his son was of age y-(x-y).
So x+y=64
x=5[y-(x-y)]
x=5[y-x+y]
x=5[2y-x]
x=10y-5x
x+5x=10y
6x=10y
x=10y/6
10y/6+y=64
10y/6+6y/6=64
16y=64*6
16y=384
y=384/16
y=24=Son's age
x+24=64
x=64-24
x=40=Father's age
y-(x-y)=24-(40-24)
=24-16
=8
Your doubt=8(son's previous age)
40=5(8)
40=40
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