Math, asked by ramakrishnasmilodon, 7 months ago

i am giving you 30 points only give me the correct procedure and solution.((( if so don't giving question not clear I am sry don't do that I will report you)))​

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Answered by IshitaAgarwal05
1

Answer:

4) 4

Step-by-step explanation:

We know that, sinx + siny = 2sin((x+y)/2).cos((x-y)/2)

Also, sinz = sin(180 - (x+y)) = sin(x+y) = 2sin((x+y)/2).cos((x+y)/2)

⇒ sinx + siny + sinz = 2sin((x+y)/2)cos((x-y)/2) + 2sin((x+y)/2)cos((x+y)/2)

⇒ sinx + siny + sinz = 2sin((x+y)/2)(cos((x-y)/2) + cos((x+y)/2))

⇒ sinx + siny + sinz = 4sin((x+y)/2)cos(x/2)cos(y/2)

⇒ sin((x+y)/2) = sin(180 - z)/2) = sin(90 - (z/2)) = cos(z/2)

⇒ sinx + siny + sinz = 4cos(x/2).cos(y/2).cos(z/2)

So, [sinx + siny + sinz]/[cos(x/2).cos(y/2).cos(z/2)]

⇒ 4[cos(x/2).cos(y/2).cos(z/2)] / [cos(x/2).cos(y/2).cos(z/2)]

4

Hope this helps.....

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