Question

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Answer 1

Explanation:

Given :-

The two consecutive sides of a rhombus are represented by 3x-6 and x+14.

To find :-

Find the Perimeter of a rhombus ?

Solution :-

Given that :

The Consecutive two sides of a rhombus = 3x-6 and x+14

We know that

All sides are equal in a rhombus

So, 3x-6 and x+14 must be equal

=> 3x-6 = x+14

=> 3x-x = 14+6

=> 2x = 20

=> x = 20/2

=> x = 10 units

Therefore,the value of x = 10 units

Now , side of the rhombus = x+14

=> 10+14

=> 24 units

Now

We know that

The Perimeter of a rhombus = 4×side units

On Substituting the value in the above formula

=> Perimeter of the rhombus = 4×24

=> Perimeter = 96 units

Answer:-

Perimeter of the given rhombus for the given problem is 96 units

Used formulae:-

• All sides are equal in a rhombus

• The Perimeter of a rhombus = 4×side units

Points to know:-

• All sides are equal.

• Digonals are not equal.

• Digonals are perpendicular bisectors to each other.

• If d1,d2 are the two diagonlos of a rhombus then Area of a rhombus = (d1d2/)/2 sq.units