I am leaving from branily app please answer this only tennetiraj86 please answer this
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Explanation:
Given :-
The two consecutive sides of a rhombus are represented by 3x-6 and x+14.
To find :-
Find the Perimeter of a rhombus ?
Solution :-
Given that :
The Consecutive two sides of a rhombus = 3x-6 and x+14
We know that
All sides are equal in a rhombus
So, 3x-6 and x+14 must be equal
=> 3x-6 = x+14
=> 3x-x = 14+6
=> 2x = 20
=> x = 20/2
=> x = 10 units
Therefore,the value of x = 10 units
Now , side of the rhombus = x+14
=> 10+14
=> 24 units
Now
We know that
The Perimeter of a rhombus = 4×side units
On Substituting the value in the above formula
=> Perimeter of the rhombus = 4×24
=> Perimeter = 96 units
Answer:-
Perimeter of the given rhombus for the given problem is 96 units
Used formulae:-
- All sides are equal in a rhombus
- The Perimeter of a rhombus = 4×side units
Points to know:-
- All sides are equal.
- Digonals are not equal.
- Digonals are perpendicular bisectors to each other.
- If d1,d2 are the two diagonlos of a rhombus then Area of a rhombus = (d1d2/)/2 sq.units
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