Question

I am not good at doing these things. Will someone PLSSSSSSSS help me?

Answer 1

ANSWER✔

$\therefore It's\:said\:that\: \\ \text{the length of a rectangle is 3 meters more than the width,}\\ \therefore \:width\:is\:represented\:as\:b \\ \dashrightarrow width=b \:m\\ \dashrightarrow length= (3+b)m\\ \therefore \:perimeter\:of\:rectangle\:is\:26m\\ perimeter\:of\:rectangle\:is\:2(l+b)\\ \implies 2[b(3+b)]=26\\ \therefore\:it\:has\:solution\: .\: we\:can\:find\:value\:of\:b\\ \large{OPTION:-C\:IS\:CORRECT}$

$\bf{\boxed{\bf{OPTION:-C, 2[(b+3)+b]=26,which\:has\:one\: solution }}}$

_____________