the 28th term and 52th tooth term of an ap are 124 and 216 respectively find the 88th term of that AP
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nth
term of AP=52
⇒ a+5d=52...(i)
And 11th term of AP=12
⇒ a+10d=112.....(ii)
Subtracting Eq(i) from Eq.(ii) we get
5d=60
∴ d= 560=12
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