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Answer 1

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Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as old as Sonu. How old are Nuri and Sonu?

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Solution

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Five years ago

Age of Nuri = x – 5 years

Age of Sony = y – 5 years

Nuri was thrice as old as Sonu

X- 5 = 3(y – 5)

X – 5 = 35 – 15

X – 3y = -15 + 5

X – 3 y = - 10 ………..(1)

Ten years later,

Age of Nuri = x + 10

Age of Sonu = y + 10

Nuri will be twice as old as Sonu.

X+ 10 = 2(y+10)

X + 10 = 2y + 20

X – 2y = 10 ………..(2)

X – 3 y = - 10 ………..(1)

Subtracting equation (1) from equation (2) we get

Y=20

Plug this value in equation first we get

X−3×20=−10

X = 60 – 10

X=50

Hence age of Nuri=50 years and age of Sonu=20 years

Explanation:

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