Question

I and m are two parallel lines intersected by
another pair of parallel lines p and a
(see Fig. 7.19). Show that A ABC=ACDA.​

Answer 1

3 x -5y = 14 , 2 x -7 y= 2 then (y, x) =

Answer 2

Step-by-step explanation:

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Solution:-

It is given that p q and l m

To prove:-

Triangles ABC and CDA are similar i.e. ΔABC ΔCDA

Proof:-

Consider the ΔABC and ΔCDA,

(i) BCA = DAC and BAC = DCA Since they are alternate interior angles

(ii) AC = CA as it is the common arm

So, by ASA congruency criterion, triangle ABC triangle CDA.

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