Question

I beg uplease help me to solve qn.b and c​

Answer 1

Answer:

b) Given PQ is a diameter of a circle.

<PTS = 60° ,

<PSQ = 90°

[Angle in a semicircle ]

i)PSQT is a cyclic quadrilateral.

<PSQ+ <PTQ = 180°

/* The pairs of opposite angles of a cyclic quadrilateral are supplementary. */

=> 90° + (60° + x) = 180°

/* From the figure */

=> 150° + x = 180°

=> x = 180° - 150° = 30°

ii ) y = x = 30°

/* Angles in the same segment are equal */

iii ) RS//PQ , PS is a transversal

z = y = 30°

/* alternate angles*/

c) <XOY + <XZY = 180°

=> 140° + <XZY = 180°

=> <XZY = 180° - 140° = 40°

•••♪