(i) Calculate the molar mass of nitric acid (HNO3).(Atomic mass of H = 1u, N = 14 u, 0 = 16 u) (ii) Calculate the number of moles in 270 gm of aluminium. (Atomic mass of Al = 27 u) (iii) Calculate the mass of 0·5 moles of helium gas. (Atomic mass of He = 4u)
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To find the molar mass of nitric acid HNO3. We need to consider the number of atoms of each element in the formula and then multiply each with the atomic mass .
In HNO3 there are 1 H atom,1 N atom and 3 O atoms
H = 1 X 1 = 1
N = 1 X 14 = 14
O = 16 X 3 = 48
16 + 14 + 1 = 63 g/mol
Answer:
63 g/mol
In HNO3 there are 1 H atom,1 N atom and 3 O atoms
H = 1 X 1 = 1
N = 1 X 14 = 14
O = 16 X 3 = 48
16 + 14 + 1 = 63 g/mol
Answer:
63 g/mol
rss210804:
Where are (ii) and (iii)
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4
i) Molar mass of HNo3
=(Atomic mass of H+Atomic mass of N+3*Atomic mass of O)
=(1+14+3*17)u
=63u
ii) 27g of Al= 1mole
1g of Al=1/27 moles
therefore, 270 g of Al =(1/27*270) mole=10 moles
iii) 1 mole of He= 4g
therefore, 0.5 moles of He=(0.5*4)=2g
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