Question

I. Calculate the number of moles and molecules of acetic acid present in 22 g of it.
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Answer 1

Answer:

answer refer to attachment.

Explanation:

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Answer 2

0.36 moles

2.167 × 10²³ molecules.

Explanation:

1 mole of acetic acid = molar mass of acetic acid

∴ 1 mole of acetic acid = 60.05 g

   x moles of acetic acid = 22 g

From cross multiplication,

x = 22 × 1/ 60.05

  = 0.36 moles acetic acid.

we know that,

1 mole = 6.022 × 10²³ molecules

∴ 0.36 moles = x molecules

    x = 6.022 × 10²³ × 0.36/1

        = 2.167 × 10²³ molecules.