Question

i) Calculate total resistance of the circuit.

ii) Magnitude of current drawn for the source.

iii) Current through R2 resistance.
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Answer 1

As R2 and R3 are in parallel ,their effective resistance will be =6×6/6+6=3

now this effective resistance and R1 are in series

i) hence total resistance=3+5=8

Now by using ohm's law V=I×R

V=12 R=8ohm

ii) hence I = 12/8=3/2A

Again R2 and R3 are in parallel hence V for them is same V=IR. As V is same ,hence I inversely proportional to R

I2/I3=R3/R2=1

as I2+I3= I=3/2

iii) hence current through R2 resistance=I2=3/4A