Math, asked by drmalik021, 1 year ago

I calculated the 2 unit vectors but I'm left with the angle ... please help me out ​

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Answers

Answered by Anonymous
1

Angle = cos^(-1) 5/7

Calculate the dot product between the vectors CA and the vector CB using formula A•B= |A||B|cos theta

then calculate the same dot product using,

A•B= a1 a2 + b1 b2 + c1c2

Where ,

A=a1 i^ + b1 j^ + c1 k^

B= a2 i^+b2 j^ + c2 k^

then use both the values of dot products from the two different formulas to calculate the value of cos theta and then theta,

Where theta is the angle between the vectors CA and the vector CB

Answered by Anonymous
1

Angle = cos^(-1) 5/7

Calculate the dot product between the vectors CA and the vector CB using formula A•B= |A||B|cos theta

then calculate the same dot product using,

A•B= a1 a2 + b1 b2 + c1c2

Where ,

A=a1 i^ + b1 j^ + c1 k^

B= a2 i^+b2 j^ + c2 k^

then use both the values of dot products from the two different formulas to calculate the value of cos theta and then theta,

Where theta is the angle between the vectors CA and the vector CB

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