Question

i challenge ---
the number of real roots of the equation (x-1)²+(x-2)²+(x-3)³=0

Answer 1

(a-b)^2=a^2-2ab+b^2
Now, (x-1)^2
= x^2-2x+1

Now, (x-2)^2
= x^2-4x+4

Now, (x-3)^3
(a-b)^3= a^3-3a^2b+3ab^2-b^3
= x^3-9x^2+27x-27


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