Question

I challenge you if u can answer!!! toughest question ever!!!​

Answer 1

Let x be the total height of the hill. Therefore, the height of the hill above the building is (x−16) and let y be the perpendicular distance from the top of the building to the hill.

We know that tanθ= Oppositeside \ Adjacentside

= BC / AB

Answer 2

Answer:

Hence, the height of the tower is: 18.6m

Step-by-step explanation:

From the figure we could see that we obtain 2 right angled triangle as:

ΔAED and ΔABC

Hence, we will apply the trignometric identity in both the triangles as:

In ΔAED

$\tan 45\degree=\dfrac{x}{l}\\\\1=\dfrac{x}{l}\\\\x=l$

Also, in ΔABC we have:

$\tan 60=\dfrac{60}{l}\\\\\sqrt{3}=\dfrac{60}{l}\\\\l=\dfrac{60}{\sqrt{3}}\\\\l=20\sqrt{3}\text{m}</p><p>$

Hence,

$x=20\sqrt{3}\text{m}$

Hence, the height of the tower is:

$16-x=16-20\sqrt{3}\\\\=16-20\times 1.73\\\\=16-34.6\\\\= 18.6\text{m}</p><p>$

Hence, the height of the tower is: 18.6m