The length of the sahdow of a pole 6m high at a certain time is 7.2 m . What is the height of another pole , the lenght of the whose shadow at that time is 27 metres ?
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Answer:
It is direct proportion
6 : 7.2 :: x : 27
6 x 27 = 7.2x
162 = 7.2x
162 / 7.2 = x
22.5 = x
The height of the second pole is 22.5m
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answer for the given problem is given
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