Question

I completed the
The distance between the parrel lines
4x +3y +7=0, 12x+9y+1=0is
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Answer 1

Answer:

4/3

Step-by-step explanation:

The lines are ,

4x+3y+7 =0 and 12x+9y+1=0

The formula for calculating distance between two parallel lines is=

$\frac{ |c2 - c1| }{ \sqrt{a {}^{2} + b {}^{2} } }$

, when we make a and b same in both equations.

So dividing equation-2 by 3,

3(4x+3y+1/3) =0

4x+3y+1/3=0

Comparing with ax+by+c1=0 and ax+by+c2=0,

a=4 , b=3 , c1= 7 , c2=1/3

Putting values in formula,

Distance between the two parallel lines is=

|7-1/3| / root(4²+3²)

= 20/3 ÷ 5

=4/3

Answer 2

Given: Lines 4x+3y+7=0 and 12x+9y+1=0 are parallel

To find: Distance between lines

The formula for calculating distance between two parallel lines is=  |c1 - c2| / √a^2 + b^2

To make a and b same in both equations; dividing 2nd equation by 3,

3(4x+3y+1/3) =0

4x+3y+1/3=0

Comparing with ax+by+c1=0 and ax+by+c2=0,

a=4 , b=3 , c1= 7 , c2=1/3

Distance between the two parallel lines is=

|7-1/3| / √(4²+3²)

= 20/3 ÷ 5

=4/3