Question

(i) Determine the nature of the roots for the quadratic equation
√3x² + 2√2x - 2/3=0​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

here

a = $\sqrt{3$

b = 2$\sqrt{2$

c = -2/3

∴ $b^{2}$ -4ac = (2$\sqrt{2$) ^2 - 4 * $\sqrt{3$ * -2/3

              = 8   - $\frac{8\sqrt{3} }{3}$

              = $\frac{24-8\sqrt{3} }{3}$

               = 8 - $\sqrt{3$

∵ $b^{2}$-4ac = 8-$\sqrt{3$ < 0

∴$\sqrt{3}$$x^{2}$ + 2$\sqrt{2$ x - 2/3 has no real roots