i dicate the probability of a natural number In one thrown of one dice
Answers
Answered by
0
Answer:
favourable outcomes = 1,2,3,4,5,6
probability of getting a natural number = 6/6 = 1
I hope this answer helps you
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Answered by
1
Step-by-step explanation:
number of natural numbers = {1,2,3,4,5,6}= 6
total outcome = {1,2,3,4,5,6}= 6
P(Natural number) =
favorable outcome/ total outcome
= 6/6 = 1
P(E) = 1
mark me as the brainliest
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