Question

I don't have any answer ​

Answer 1

hope it will help you....

Answer 2

Answer:

First let us assume that

$\sqrt{3} + 5$

is an rational number

Step-by-step explanation:

then,

$\sqrt{3 } + 5 = p \div q$

ie, √3= p/q-6

ie, √3=p-5q/q (where p and q are co-primes and q is not equal to zero)

Therefore p, q are integers,

therefore p-5q/q is a rational number

But we know that √3 is irrational

This contradiction has arisen because our assumption is wrong.

therefore √3 +5 is an irrational number

If it is not given in the question, also prove that √3 is irrational

hope this helps u:-)