Math, asked by tania1234, 10 months ago

I don't know the answer please help me

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Answers

Answered by Happypincha111
1

see the question ....properly ... the part 1/1+x is same in both the sides .... they will get cancelled out and

the remains will be x=-1

so the answer is one value

Answered by Swarup1998
5

Answer :

" Option (4) >> No value " is correct

Step by step solution :

The given equation is

x+\frac{1}{x+1}=-1+\frac{1}{x+1}

\implies \frac{x(x+1)+1}{x+1}=\frac{-(x+1)+1}{x+1}

\implies \frac{x^{2}+x+1}{x+1}=\frac{-x-1+1}{x+1}

\implies x^{2}+x+1=-x

         where x + 1 ≠ 0

\implies x^{2}+2x+1=0

\implies (x+1)^{2}=0

\implies x+1=0

  But previously, we have taken (x + 1) to be non-zero in order to simplify. This is a contradiction.

  Thus, the given equation has no solution or no value of x.

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